IBM C2090-545 exam dumps : DB2 9.7 SQL Procedure Developer

  • Exam Code: C2090-545
  • Exam Name: DB2 9.7 SQL Procedure Developer
  • Updated: Oct 18, 2026     Q & A: 115 Questions and Answers

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IBM C2090-545 Exam Syllabus Topics:

SectionObjectives
Topic 1: DB2 Stored Procedures Development- Cursors and result sets
- Parameter handling (IN, OUT, INOUT)
- Dynamic SQL usage in procedures
Topic 2: Database Objects and Transaction Control- Locks and concurrency control
- Transactions and commit/rollback behavior
Topic 3: DB2 Environment and Programming Concepts- Security and privileges for procedure execution
- DB2 architecture overview
Topic 4: Error Handling and Debugging- Exception and condition handlers
- SQLSTATE and SQLCODE handling
Topic 5: SQL Procedures and SQL PL Basics- SQL procedural language (SQL PL) syntax and structure
- Creating and managing SQL procedures
- Variables, control statements, and flow logic

IBM DB2 9.7 SQL Procedure Developer Sample Questions:

Question #1

Given the SQL statement shown below:

Which statement correctly describes the cursor MY_CURSOR?

  • A. The cursor does not have sensitivity to insert, update, or delete operations that are made to rows in the underlying result table.
  • B. The cursor can be used to perform positioned delete operations.
  • C. The result table of the cursor is intended to be used as a result set that will be returned from a procedure.
  • D. The cursor will not be closed as a consequence of a commit operation.
Reveal Solution  Discussion  0

Correct Answer: B  🗳️

Question #2

Given the statement shown below:

What happens to NEWPROD if 'http://posample.org/product.xsd' is dropped?

  • A. NEWPROD will raise an exception.
  • B. NEWPROD will validate against a new schema.
  • C. NEWPROD is marked as inoperative.
  • D. NEWPROD is dropped.
Reveal Solution  Discussion  0

Correct Answer: C  🗳️

Question #3

Which steps must be followed to return a result set from an SQL procedure?

  • A. 1. Create the procedure using the WITH RETURN clause.
    2.Declare the cursor using the DYNAMIC RESULT SETS clause.
    3.Open the cursor in the SQL procedure.
    4.Close the cursor.
  • B. 1. Create the procedure using the DYNAMIC RESULT SETS clause.
    2.Declare the cursor.
    3.Open the cursor in the SQL procedure.
    4.Close the cursor.
    5.Return to the application.
  • C. 1. Create the procedure using the WITH RETURN clause.
    2.Declare the cursor using the DYNAMIC RESULT SETS clause.
    3.Open the cursor in the SQL procedure.
    4.Return to the application.
  • D. 1. Create the procedure using the DYNAMIC RESULT SETS clause.
    2.Declare the cursor using the WITH RETURN clause.
    3.Open the cursor in the SQL procedure.
    4.Return to the application.
Reveal Solution  Discussion  0

Correct Answer: D  🗳️

Question #4

Which object is used to return a result set from an SQL procedure?

  • A. Scratchpad
  • B. Temporary table
  • C. Array
  • D. Cursor
Reveal Solution  Discussion  0

Correct Answer: D  🗳️

Question #5

Which code fragment illustrates the proper way to capture and save SQL error handler values so they can be used to control procedure logic?

  • A. DECLARE CONTINUE HANDLER FOR SQLEXCEPTION, SQLWARNING, NOT FOUND SET retcode = SQLCODE;
  • B. DECLARE ERROR HANDLER FOR SQLEXCEPTION, SQLWARNING, NOT FOUND SET retcode = EXCEPTION;
  • C. DECLARE ERROR HANDLING SQLEXCEPTION, SQLWARNING, NOT FOUND SET retcode = SQLERRN;
  • D. DECLARE ERROR HANDLING FOR SQLEXCEPTION, SQLWARNING, NOT FOUND SET retcode = SQLMSG;
Reveal Solution  Discussion  0

Correct Answer: A  🗳️

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